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0.05x^2-44x+1200=0
a = 0.05; b = -44; c = +1200;
Δ = b2-4ac
Δ = -442-4·0.05·1200
Δ = 1696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1696}=\sqrt{16*106}=\sqrt{16}*\sqrt{106}=4\sqrt{106}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-4\sqrt{106}}{2*0.05}=\frac{44-4\sqrt{106}}{0.1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+4\sqrt{106}}{2*0.05}=\frac{44+4\sqrt{106}}{0.1} $
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